河南省2023-2024学年度八年级第三次12月月考(三)数学
河南省2023-2024学年度八年级第三次12月月考(三)数学试卷答案,我们目前收集并整理关于河南省2023-2024学年度八年级第三次12月月考(三)数学得系列试题及其答案,更多试题答案请关注我们
河南省2023-2024学年度八年级第三次12月月考(三)数学试卷答案
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74.你需要在朋友们来之前把房间整理好
you."Youneedtostraightenyourroombeforeyourfriendscomeover."Protectmefromwhat?Havingfun?"Herolledhiseyesandwalkedaway.75.这种纸的材料和水接触后易于分解
Isighed,tryingtoholdbackmytears.HowcouldImakeJordanseethatthoserulesexistedThiskindofpaperismadeofamaterialthatbreakseasilywhenexposedtowaterbecauseIlovehim,notbecauseIwastryingtocontrolhim.76.我走不到公园,咱们坐公交吧
Idecidedtogoforawalk,hopingthecoolOctoberairwouldclearmyhead.IopenedtheI'mnotupwalkingtothepark.Let'stakeabus.frontdoorandnearlysteppedonhim:Meatball,thesmallblackcatwehadadoptedtwoweeks77.猫常常整天睡觉,而狗从不安稳
ago.Thecatswilloftensleepthedayaway.Thedogs,contrast,neversettledown.Meatballusedtobeahomelesscatanduntilnowhestillhadn'tadjustedtothelifeofa78.他们坚决要求再给一次竞争的机会
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OnesnowynightinJanuary,thetemperaturewasunusuallylow.Meatballstoodatthedoor,YuanLongpingreallycaredaboutwasnotmoneyorcelebrity.beggingtogooutsideagain.Ipattedhishead,tellinghimtostayinforhisowngoodorhe第五部分书写(5分)wouldfreeze.Jordanwhistlednearbyandwentintohisroom.请按照书写格式和要求抄写以下内容
注意:TuYouyouwasbornin1930inNingbo,China.Herfamilystressededucationforher,but1.续写词数应为150左右:shehadtotakeatwo-yearbreakfromstudyingat16becauseshehadcontractedtuberculosis.2.开头已给出Whenshereturnedtoschool,sheknewexactlywhatshewantedtostudy-medicine.Shewantedtofindcuresfordiseasesliketheonethathadafflictedher.Thenextmorning,IfoundMeatballmissing.第六部分写作(满分25分)阅读下面材料,根据其内容和所给段落开头语续写两段,使之构成一篇完整的短文
$Parentingteenagerswaschallenging.Foralongtime,IcouldfeelthetensionbetweenJordan,,myteenagesonandme,especiallyoverhiscurfew..(儿童晚归时间的规定)Onthedrivehomefromtheanimaldoctor'soffice,pettingMeatball'shead,JordanOneSundayafternoon,theunpleasantdiscussionhappenedagain.apologizedtome."I'mseventeenyearsold,butIstillhaveacurfew.Noneofmyfriendshasacurfew.Youdon'ttrustme."Jordansaid"It'snotabouttrust,"Isaid."It'saboutwantingwhat'sbestforyouandIwanttoprotect高二英语试卷第11页(共12页)高二英语试卷第12页(共1页)
分析根据零点的存在性定理可知f(x)在零点所在区间端点的函数值异号,逐个验证可得答案.
解答解:∵f(0)=-3<0,f($\frac{1}{2}$)=$\sqrt{e}$-3<0,f(1)=e-2>0,
∴f(x)的零点在区间($\frac{1}{2}$,1)上.
故选B.
点评本题考查了零点的存在性判断,是基础题.