20.解:(1)x=(36.2×0.2+36.4×0.25+36.6×0.7+36.8×0.8+37×1.1+37.2×0.8+37.4×0.65+37.6×0.4+37.8×0.05+38×0.05)×0.2=37
所以P(36.4≤X≤37.6)=0.9544
所以恰好有一颗不是“标准果”的概率P=C28×0.9544”×(1-0.9544)≈0.38
[江门一模]广东省江门市2022年高考模拟考试数学答案
20.解:(1)x=(36.2×0.2+36.4×0.25+36.6×0.7+36.8×0.8+37×1.1+37.2×0.8+37.4×0.65+37.6×0.4+37.8×0.05+38×0.05)×0.2=37
所以P(36.4≤X≤37.6)=0.9544
所以恰好有一颗不是“标准果”的概率P=C28×0.9544”×(1-0.9544)≈0.38
[江门一模]广东省江门市2022年高考模拟考试数学答案